83 practice questions on Wave Optics , sorted Easy → Hard. Try each one first, then open its answer page for the worked explanation. Want the full theory first? Read the Wave Optics notes .
Young's Double Slit Experiment source slits S₁,S₂ d screen bright dark Path difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.
Easy - 25 questions Q1.
The spreading of light into the geometrical shadow region behind an obstacle is called:
A diffractionB reflectionC refractionD dispersionShow answer & explanation →
Q2.
Two independent light bulbs cannot act as coherent sources because the phase difference between them:
A remains constant in timeB keeps changing randomlyC is exactly zeroD is exactly 90°Show answer & explanation →
Q3.
In Young double-slit experiment, using light of larger wavelength makes the fringe width:
A decreaseB become zeroC increaseD stay the sameShow answer & explanation →
Q4.
Sound waves cannot be polarised because they are:
A transverse wavesB electromagnetic wavesC high-frequency wavesD longitudinal wavesShow answer & explanation →
Q5.
A point source of light placed at the focus of a convex lens produces a:
A plane wavefrontB spherical wavefrontC cylindrical wavefrontD converging wavefrontShow answer & explanation →
Q6.
Huygens' principle states that every point on a wavefront acts as a source of:
A Secondary waveletsB Primary raysC PhotonsD Interference fringesShow answer & explanation →
Q7.
In Young's double slit experiment, bright fringes occur when the path difference is:
A nλ (integer multiple of wavelength)B (2n-1)λ/2, the condition for destructive interferenceC nλ/2, half the integer-multiple conditionD (2n+1)λ, an odd multiple offset from the true conditionShow answer & explanation →
Q8.
Fringe width in YDSE is given by β = λD/d. Increasing the slit separation d will:
A Decrease the fringe widthB Increase the fringe widthC Not affect the fringe widthD Make fringes disappearShow answer & explanation →
Q10.
Which phenomenon cannot be explained by the wave theory of light?
A Photoelectric effectB Interference in most textbook accountsC Diffraction during normal conditionsD Polarization as generally observedShow answer & explanation →
Q11.
Malus's law states that when polarized light of intensity I<sub>0</sub> passes through an analyser at angle θ:
A I = I<sub>0</sub> cos²θB I = I<sub>0</sub> sin²θC I = I<sub>0</sub>/cosθD I = I<sub>0</sub> cosθShow answer & explanation →
Q12.
When unpolarized light of intensity I<sub>0</sub> passes through a single polaroid, the transmitted intensity is:
A I<sub>0</sub>/2B I<sub>0</sub>C I<sub>0</sub>/4D 0Show answer & explanation →
Q13.
Coherent sources must have:
A Same frequency and constant phase differenceB Identical amplitude mainly, with phase free to drift randomlyC Identical wavelength mainly, with frequency free to varyD Identical intensity mainly, with little constraint on phaseShow answer & explanation →
Q14.
In YDSE, the central bright fringe is located at:
A The midpoint between the two slits on the screenB Directly behind the first slit on the screenC Directly behind the second slit on the screenD At the outer edges of the illuminated screen regionShow answer & explanation →
Q15.
Diffraction of light is most prominent when the obstacle size is:
A Comparable to the wavelength of lightB Much larger than the wavelengthC Much smaller than the wavelengthD Exactly twice the wavelengthShow answer & explanation →
Q17.
In a single slit diffraction pattern, the first minimum occurs at:
A sinθ = λ/a (a = slit width)B sinθ = λ/2a, half the correct angular conditionC sinθ = 2λ/a, double the correct angular conditionD sinθ = a/λ, the reciprocal of the correct ratioShow answer & explanation →
Q20.
When a YDSE is submerged in a liquid of refractive index n, the fringe width:
A Decreases by factor nB Increases by factor nC Remains sameD DoublesShow answer & explanation →
Q21.
Diffraction grating produces a spectrum because:
A Different wavelengths diffract at different anglesB All wavelengths diffract at the same angle in typical laboratory settingsC Light is absorbed selectively under usual circumstancesD The grating polarizes light according to most researchersShow answer & explanation →
Q22.
Newton's rings are formed due to:
A Interference of light reflected from two surfaces of an air wedgeB Diffraction of light bending around the lens edge in the majority of cases studiedC Polarization of light by the curved glass surface as widely reportedD Scattering of light by the glass lens material in standard practiceShow answer & explanation →
Q23.
If the distance between slits in YDSE is doubled (other factors constant), the number of fringes visible in the same region:
A DoublesB HalvesC Stays sameD QuadruplesShow answer & explanation →
Q24.
For the condition of destructive interference, path difference must equal:
A Odd multiples of λ/2: λ/2, 3λ/2, 5λ/2...B Even multiples of λ/2: λ, 2λ, 3λ...C ZeroD Any valueShow answer & explanation →
Q25.
The resolving power of a telescope depends on:
A The diameter of the objective lensB The focal length of the eyepieceC The magnificationD The colour of lightShow answer & explanation →
Medium - 24 questions Q26.
In a Young double-slit experiment d = 0.5 mm, D = 1 m and λ = 500 nm. The distance of the third bright fringe from the central maximum is:
Show answer & explanation →
Q27.
A thin transparent sheet (μ = 1.6, thickness 2 μm) is placed over one slit in a double-slit setup using λ = 600 nm. The central fringe shifts by:
A 4 fringesB 1 fringeC 2 fringesD 6 fringesShow answer & explanation →
Q28.
Plane polarised light of intensity I<sub>0</sub> falls on an analyser whose axis is at 30° to the polarisation direction. The transmitted intensity is:
A I<sub>0</sub>/2B I<sub>0</sub>/4C I<sub>0</sub>D 3I<sub>0</sub>/4Show answer & explanation →
Q29.
Light reflected from the surface of a transparent medium is found to be completely plane polarised at an angle of incidence of 60°. The refractive index of the medium is:
Show answer & explanation →
Q30.
In YDSE with slit separation d = 0.5 mm, screen at D = 1 m, λ = 500 nm. What is the fringe width?
A 1 mmB 0.5 mmC 2 mmD 0.25 mmShow answer & explanation →
Q31.
If the 5th bright fringe in YDSE is at 2.5 mm from centre with D = 1 m and d = 1 mm, what is the wavelength?
A 500 nmB 250 nmC 1000 nmD 400 nmShow answer & explanation →
Q32.
In YDSE, if one slit is covered, the fringe pattern:
A Disappears and single diffraction pattern remainsB Doubles in fringe width while interference continues normallyC Shifts entirely to one side of the screen but persistsD Remains exactly the same as with both slits openShow answer & explanation →
Q33.
Polarized light of intensity I<sub>0</sub> passes through two polaroids with angle θ = 60° between them. Final transmitted intensity is:
A I<sub>0</sub>/4B I<sub>0</sub>/2C I<sub>0</sub> cos 60°D I<sub>0</sub> cos² 30°Show answer & explanation →
Q34.
The central maximum in single slit diffraction is:
A Twice as wide as any other maximumB Same width as other maxima in the majority of cases studiedC Half as wide as widely reportedD Not present in standard practiceShow answer & explanation →
Q35.
In a thin film of thickness t and refractive index n, the condition for constructive interference (reflected light) when light is incident from air is:
A 2nt = (2m+1)λ/2 (half-wave loss at first surface)B 2nt = mλ, the condition ignoring the half-wave phase lossC 2t = mλ/n, omitting the refractive index from the optical pathD 2nt = mλ/2, half the correct optical path conditionShow answer & explanation →
Q36.
In YDSE, when a mica sheet of thickness t and refractive index μ is placed in front of one slit, the central fringe shifts toward:
A The slit with the mica sheetB The other slitC Does not shiftD Depends on wavelengthShow answer & explanation →
Q37.
If a diffraction grating has 500 lines per mm, what is the grating element d?
A 2 μmB 500 nmC 1 mmD 0.002 mmShow answer & explanation →
Q38.
Unpolarized light (I<sub>0</sub>) passes through polaroid P<sub>1</sub>, then through P<sub>2</sub> at 30° to P<sub>1</sub>, then through P<sub>3</sub> at 90° to P<sub>1</sub>. Final intensity is:
A 3I<sub>0</sub>/16B I<sub>0</sub>/8C I<sub>0</sub>/4D I<sub>0</sub>/2Show answer & explanation →
Q39.
The angular position of second-order maximum for a diffraction grating with d = 2μm and λ = 500 nm is:
A sinθ = 0.5, θ = 30°B θ = 60° under most conditions encounteredC θ = 45° as frequently observed in practiceD θ = 15° in many documented casesShow answer & explanation →
Q40.
The Rayleigh criterion for the limit of resolution of a telescope (objective diameter D) is:
A θ_min = 1.22λ/DB θ_min = λ/DC θ_min = D/λD θ_min = 2λ/DShow answer & explanation →
Q41.
In YDSE, what happens to the fringe pattern when white light is used instead of monochromatic light?
A Coloured fringes with white central bright fringeB No fringe pattern forms with white light presentC Generally black and white alternating fringes with little colourD Mainly red-coloured fringes appear across the entire screenShow answer & explanation →
Q42.
A glass plate of thickness 0.5 mm and μ = 1.5 is placed in the path of one beam in YDSE (λ = 600 nm). By how many fringes does the pattern shift?
Show answer & explanation →
Q44.
In the double slit experiment, the intensity at a point where the path difference is λ/4 is (I<sub>0</sub> = intensity at central max):
A I<sub>0</sub>/2B I<sub>0</sub>/4C 0D I<sub>0</sub>Show answer & explanation →
Q45.
Interference fringes in Young's experiment have visibility (contrast). Visibility is maximum when:
A Both slits have equal intensitiesB One slit is blockedC The slits are very far apartD The screen is very closeShow answer & explanation →
Q46.
What is the maximum number of orders visible for a grating with d = 3λ?
A 3 (n = 1, 2, 3)B 2C 6D InfiniteShow answer & explanation →
Q47.
The wavefront of a point source at large distance becomes approximately:
A Plane wavefrontB Spherical wavefrontC Cylindrical wavefrontD Elliptical wavefrontShow answer & explanation →
Q48.
In Lloyd's mirror experiment, the fringe pattern is similar to YDSE but the central fringe is:
A Dark (due to half-wave loss on reflection)B Bright, exactly as in the ordinary double-slit setupC Not present, unlike the ordinary double-slit setupD Distinctly coloured even under generally monochromatic lightShow answer & explanation →
Q49.
If the slit width in single-slit diffraction is halved, the central maximum width:
A DoublesB HalvesC QuadruplesD Stays sameShow answer & explanation →
Hard - 34 questions Q50.
In a two-slit interference pattern the intensity at the central maximum is I<sub>0</sub>. At a point where the path difference is λ/3, the intensity is:
A I<sub>0</sub>B I<sub>0</sub>/2C 3I<sub>0</sub>/4D I<sub>0</sub>/4Show answer & explanation →
Q51.
Two coherent sources of intensity I and 9I interfere. The ratio of maximum to minimum intensity in the pattern is:
Show answer & explanation →
Q52.
A telescope objective has diameter 5 cm and is used with light of wavelength 550 nm. Its limit of angular resolution is about:
A 1.34×10<sup>-4</sup> radB 6.7×10<sup>-5</sup> radC 2.7×10<sup>-5</sup> radD 1.34×10<sup>-5</sup> radShow answer & explanation →
Q53.
In a double-slit experiment light of 480 nm and 600 nm illuminates the slits together. The bright fringes first coincide at:
A 5th order of 480 nm with 4th order of 600 nmB 4th order of 480 nm with 5th order of 600 nmC 6th order of 480 nm with 5th order of 600 nmD 3rd order of 480 nm with 2nd order of 600 nmShow answer & explanation →
Q54.
The minimum thickness of a soap film (n = 1.33) that appears bright in reflected light for λ = 532 nm is:
A 200 nmB 100 nmC 133 nmD 50 nmShow answer & explanation →
Q55.
A diffraction grating has 6000 lines per cm and is used with light of wavelength 589 nm. The maximum order of the spectrum observable is:
Show answer & explanation →
Q56.
In YDSE, the ratio of intensities at maxima and minima is 9:1. What is the ratio of amplitudes of the two sources?
Show answer & explanation →
Q57.
In YDSE, slits are separated by d, screen at D. A point source is placed at distance D from the slits, off-axis by y<sub>0</sub>. The central fringe shifts by:
A y<sub>0</sub> (fringes shift toward the source)B y<sub>0</sub>/2, half the actual shift produced by the displaced sourceC 2y<sub>0</sub>, twice the actual shift produced by the displaced sourceD y<sub>0</sub> D/d, an expression with the wrong dependence on slit separationShow answer & explanation →
Q58.
Light of wavelengths 400 nm and 600 nm is used in YDSE. What is the minimum distance from centre where fringes coincide?
A 6β_600 = 4β_600 = bright fringe at 3 mm if D=1m, d=0.2mmB 4β for 600 nmC 6β for 400 nmD 12β for bothShow answer & explanation →
Q59.
In a diffraction grating, for the n-th order spectrum of wavelength λ_1 to overlap with the (n+1)-th order of λ_2, we need:
A nλ_1 = (n+1)λ_2B λ_1 = λ_2C nλ_1 = nλ_2D (n+1)λ_1 = nλ_2Show answer & explanation →
Q60.
A thin soap film (t = 400 nm, n = 1.33) is illuminated by white light. Which wavelength of reflected light is most intensified?
A 424 nm (violet-blue)B 532 nm (green)C 700 nm (red)D 800 nm (infrared)Show answer & explanation →
Q61.
In YDSE, the n-th dark fringe from centre is at distance y from centre. If the screen moves farther, what happens to y?
A y increases proportionally with DB y decreasesC y stays sameD y depends only on wavelengthShow answer & explanation →
Q63.
Two coherent waves I<sub>1</sub> = 4I and I<sub>2</sub> = I interfere. The maximum and minimum intensities are:
A 9I and IB 5I and 3IC 4I and ID 16I and 0Show answer & explanation →
Q64.
In single-slit diffraction, the intensity at angle θ from centre follows I = I<sub>0</sub> (sinα/α)² where α = πa sinθ/λ. At what value of α is the first secondary maximum approximately?
Show answer & explanation →
Q65.
A Michelson interferometer moves one mirror by 0.1 mm. If 200 fringes pass the reference, what is the wavelength?
A 1000 nmB 500 nmC 200 nmD 100 nmShow answer & explanation →
Q66.
In YDSE with glass slabs of thickness t<sub>1</sub> and t<sub>2</sub> and refractive indices n<sub>1</sub> and n<sub>2</sub> placed in front of slits, the shift of central fringe is:
A (n<sub>1</sub>-1)t<sub>1</sub> - (n<sub>2</sub>-1)t<sub>2</sub> divided by λ (in terms of fringes)B (t<sub>1</sub>-t<sub>2</sub>)/λ, omitting the refractive indices entirely from the path differenceC (n<sub>1</sub> t<sub>1</sub> - n<sub>2</sub> t<sub>2</sub>)/λ, omitting the subtraction of unity from each indexD (n<sub>1</sub>+n<sub>2</sub>)(t<sub>1</sub>-t<sub>2</sub>)/λ, an incorrect combination of the indices and thicknessesShow answer & explanation →
Q67.
The condition for maximum intensity in Newton's rings (dark central spot) is that the n-th bright ring has radius:
A r<sub>n</sub> = √((2n-1)λR/2) for n=1,2,3...B r<sub>n</sub> = √(nλR), the formula for dark rings instead of bright ringsC r<sub>n</sub> = nλR, omitting the square root from the correct expressionD r<sub>n</sub> = √(2nλR), missing the half-integer offset of the bright-ring conditionShow answer & explanation →
Q68.
Two slits separated by 0.2 mm are illuminated by coherent light of 600 nm. A screen is 1.5 m away. The number of bright fringes between the two direct beams from the slits is approximately:
Show answer & explanation →
Q69.
When a biprism (Fresnel biprism) is used in optics, the two virtual coherent sources are created by:
A Refraction through the two halves of the prismB Reflection from two separate plane mirrors, as in Fresnel's mirror setupC Diffraction of light passing through two narrow physical slitsD Total internal reflection occurring inside the glass of the biprismShow answer & explanation →
Q70.
The angular width of the central maximum in single-slit diffraction doubles when:
A The slit width is halvedB The wavelength is halvedC The screen distance is halvedD The slit width is doubledShow answer & explanation →
Q71.
In YDSE, if the distance between slits is increased 4 times while the distance to screen is halved, by what factor does fringe width change?
Show answer & explanation →
Q72.
What is the minimum thickness of a glass film (n=1.5) that appears dark in reflected light for λ = 600 nm?
A 200 nmB 100 nmC 300 nmD 400 nmShow answer & explanation →
Q73.
In a diffraction grating experiment, the 4th order for λ = 500 nm and the n-th order for λ = 625 nm coincide. Find n.
Show answer & explanation →
Q75.
The coherence length of light is the path difference over which interference can be observed. For sodium light (Δλ = 0.6 nm, λ = 589 nm), the coherence length is approximately:
A 0.58 mmB 5.8 mmC 0.058 mmD 58 mmShow answer & explanation →
Q76.
In a Young double-slit experiment, λ = 600 nm, slit separation 1 mm, and screen distance 1 m. The fringe width is:
A 0.06 mmB 0.6 mmC 1.2 mmD 6 mmShow answer & explanation →
Q77.
In a double-slit experiment, if the screen distance is doubled (other things fixed), the fringe width:
A halvesB doublesC becomes four timesD is unchangedShow answer & explanation →
Q78.
In a two-slit interference pattern, the condition for a bright fringe (constructive interference) is a path difference of:
A nλB (n + 1/2)λC nλ/2D λ/4Show answer & explanation →
Q79.
For single-slit diffraction of a slit of width a, the first minimum occurs at an angle satisfying:
A a sinθ = λ/2B a sinθ = λC a sinθ = 2λD d sinθ = λShow answer & explanation →
Q80.
A Young double-slit apparatus is immersed in water (n = 1.33). Compared with air, the fringe width:
A decreasesB increasesC is unchangedD becomes zeroShow answer & explanation →
Q82.
For sustained interference, the two light sources must be:
A coherent, with a constant phase differenceB of different frequenciesC of equal amplitude onlyD of random phaseShow answer & explanation →
Q83.
The phenomenon of polarization of light establishes that light is a:
A longitudinal waveB transverse waveC particle streamD standing waveShow answer & explanation →