83 practice questions on Thermodynamics , sorted Easy → Hard. Try each one first, then open its answer page for the worked explanation. Want the full theory first? Read the Thermodynamics notes .
Carnot Cycle (P-V Diagram) V P 1→2: isothermal expansion (T_H) 2→3: adiabatic expansion 3→4: isothermal compression (T_C) 4→1: adiabatic compression 1 2 3 4 Net work done by the gas = area enclosed by the loop 1→2→3→4→1 The Carnot cycle alternates two isothermal steps (heat absorbed at TH , released at TC ) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC /TH is the maximum possible efficiency between those two temperatures.
Easy - 24 questions Q1.
A thermodynamic process carried out at constant pressure is called:
A isobaricB isochoricC isothermalD adiabaticShow answer & explanation →
Q2.
On a P-V diagram, the area under the curve represents:
A the heat absorbedB the work done by the gasC the internal energyD the change in entropyShow answer & explanation →
Q3.
No engine can be more efficient than a Carnot engine between the same two temperatures. This follows from:
A the first law of thermodynamicsB Boyle lawC the zeroth lawD the second law of thermodynamicsShow answer & explanation →
Q4.
A quasi-static process is best described as one that is:
A carried out extremely slowlyB completed as fast as possibleC always adiabatic in natureD always done at fixed volumeShow answer & explanation →
Q7.
The first law of thermodynamics is basically:
A Entropy always increasesB Conservation of energyC Heat flows from cold to hotD Temperature is absoluteShow answer & explanation →
Q8.
During an isothermal process:
A Pressure is constantB Temperature is constantC Volume is constantD Heat is not exchangedShow answer & explanation →
Q9.
In an adiabatic process:
A No work is doneB Temperature is constantC No heat is exchangedD Volume is constantShow answer & explanation →
Q11.
Zeroth law of thermodynamics defines:
A EntropyB Temperature scaleC Conservation of energyD Heat engine efficiencyShow answer & explanation →
Q13.
The second law of thermodynamics states that entropy of an isolated system:
A Always decreases toward a minimum equilibrium valueB Stays exactly constant for every real spontaneous processC Always increases or stays constantD Fluctuates randomly with no preferred direction over timeShow answer & explanation →
Q14.
Boyle's law states that at constant temperature:
A P is proportional to VB P is proportional to 1/VC V is proportional to TD P is proportional to TShow answer & explanation →
Q15.
Q = mcT formula is used to calculate:
A Latent heat overallB Specific heat in most casesC Sensible heat exchangeD Enthalpy under typical conditionsShow answer & explanation →
Q17.
A refrigerator works on which principle?
A Converts heat completely to work with no external inputB Moves heat from cold to hot body using work inputC Permanently destroys heat energy via friction in the compressorD Creates a cold region from nothing, violating energy conservationShow answer & explanation →
Q19.
Charles law states that at constant pressure:
A PV = constantB V/T = constantC P/T = constantD PV/T = constantShow answer & explanation →
Q20.
Latent heat is the heat exchanged during:
A Temperature changeB Phase changeC Pressure changeD Volume changeShow answer & explanation →
Q21.
Thermal efficiency of a heat engine is defined as:
A Work output / Heat inputB Heat output / Heat inputC Heat input / Work outputD Work output / Heat rejectedShow answer & explanation →
Q22.
In an isochoric (constant volume) process, work done by the gas is:
A MaximumB MinimumC ZeroD Equal to heat addedShow answer & explanation →
Q24.
Heat flows spontaneously from:
A Cold to hot bodyB Hot to cold bodyC Either directionD Only at phase changesShow answer & explanation →
Medium - 26 questions Q25.
In one complete cycle a gas takes in 500 J of heat from a hot source and 300 J from a second source, and rejects 200 J to a cold sink. The net work done by the gas over the cycle is:
A 600 JB 1000 JC 400 JD 800 JShow answer & explanation →
Q26.
Two moles of a monatomic ideal gas are warmed from 300 K to 400 K at constant pressure (R = 8.31 J/mol K). The work done by the gas is about:
A 3320 JB 1662 JC 831 JD 2493 JShow answer & explanation →
Q27.
A Carnot engine rejects heat to a sink at 300 K and runs at 40% efficiency. To lift its efficiency to 50% with the same sink temperature, the source temperature must be raised by:
A 100 KB 50 KC 200 KD 150 KShow answer & explanation →
Q28.
A gas releases 100 J of heat while 40 J of work is done on it. The change in its internal energy is:
A -140 JB -60 JC -100 JD +60 JShow answer & explanation →
Q29.
A gas expands at constant pressure 2 × 10<sup>5</sup> Pa from 2 L to 5 L. The work done by the gas is:
A 200 JB 1000 JC 600 JD 300 JShow answer & explanation →
Q30.
2 moles of a monatomic ideal gas are heated at constant volume by 100 K (R = 8.31 J/mol K). The heat supplied is:
A ≈1250 JB ≈2490 JC ≈4150 JD ≈3740 JShow answer & explanation →
Q31.
1 mole of ideal gas at 27 degrees C has internal energy (Cv = 3R/2 for monatomic):
A 300 JB 1247 JC 3741 JD 4988 JShow answer & explanation →
Q32.
An ideal gas expands isothermally. Work done by gas:
A Is zeroB Is positiveC Is negativeD Equals change in internal energyShow answer & explanation →
Q33.
A Carnot engine has 60% efficiency. If cold reservoir is at 300 K, hot reservoir temperature:
A 500 KB 600 KC 750 KD 900 KShow answer & explanation →
Q34.
For a gas expanding adiabatically, gamma = Cp/Cv = 5/3. If pressure halves, volume changes by factor:
A 2B 2<sup>3/5</sup>C 2<sup>5/3</sup>D 3/5Show answer & explanation →
Q37.
1 kg of water at 100 degrees C converts to steam. Latent heat of vaporization = 2.26 x 10<sup>6</sup> J/kg. Heat required:
A 2260 JB 22600 JC 226000 JD 2260000 JShow answer & explanation →
Q38.
Heat engine takes 1000 J from hot source, does 400 J of work. Heat rejected to cold reservoir:
A 400 JB 500 JC 600 JD 1000 JShow answer & explanation →
Q41.
For an ideal gas, relation between Cp and Cv is:
A Cp = Cv + RB Cp = Cv - RC Cp = gamma x CvD Cp = Cv / RShow answer & explanation →
Q43.
Work done by an ideal gas in an isobaric expansion from V<sub>1</sub> to V<sub>2</sub> at pressure P:
A P(V<sub>2</sub>-V<sub>1</sub>)B (V<sub>2</sub>-V<sub>1</sub>)/PC P(V<sub>2</sub>+V<sub>1</sub>)D PV<sub>2</sub>/V<sub>1</sub>Show answer & explanation →
Q44.
Coefficient of performance (COP) of a refrigerator is:
A W/Q<sub>cold</sub>B Q<sub>cold</sub>/WC Q<sub>hot</sub>/WD W/Q<sub>hot</sub>Show answer & explanation →
Q45.
At absolute zero (0 K), all molecular motion:
A Is maximumB Stops completelyC Continues at minimum levelD Is undefinedShow answer & explanation →
Q50.
If temperature of a gas doubles (at constant pressure), its volume:
A HalvesB Stays sameC DoublesD QuadruplesShow answer & explanation →
Hard - 33 questions Q51.
A monatomic ideal gas (γ = 5/3) at 300 K is compressed adiabatically to one-eighth of its original volume. The final temperature is:
A 600 KB 900 KC 1200 KD 2400 KShow answer & explanation →
Q52.
Two Carnot engines work in series: the first between 800 K and an intermediate temperature T, the second between T and 200 K. If both engines have equal efficiency, T equals:
A 600 KB 500 KC 300 KD 400 KShow answer & explanation →
Q53.
A Carnot engine absorbs 600 J at 400 K and rejects heat to a sink at 300 K. The work it does per cycle is:
A 600 JB 450 JC 300 JD 150 JShow answer & explanation →
Q55.
1 mole of a monatomic ideal gas expands adiabatically as its temperature falls from 400 K to 300 K (R = 8.31). The work done by the gas is about:
A ≈623 JB ≈831 JC ≈1250 JD ≈2490 JShow answer & explanation →
Q56.
One mole of ideal gas undergoes cycle: isothermal expansion at T<sub>1</sub>, then cooling to T<sub>2</sub>, then isothermal compression, then heating. This is a:
A Carnot cycleB Rankine cycleC Otto cycleD Diesel cycleShow answer & explanation →
Q57.
1 mole of diatomic gas (Cv = 5R/2) undergoes isochoric heating from 300K to 600K. Heat added:
A 1247 JB 4157 JC 6235 JD 8314 JShow answer & explanation →
Q58.
Carnot efficiency = 80%. If cold reservoir is at 400 K, hot reservoir is at:
A 1600 KB 2000 KC 3200 KD 800 KShow answer & explanation →
Q59.
An ideal gas undergoes free expansion into vacuum (Q=0, W=0). Temperature change:
A IncreasesB DecreasesC Remains sameD Depends on gasShow answer & explanation →
Q60.
Work done during isothermal expansion of n moles from V<sub>1</sub> to V<sub>2</sub> at temperature T:
A nRT ln(V<sub>2</sub>/V<sub>1</sub>)B nRT(V<sub>2</sub>-V<sub>1</sub>)C nRT(V<sub>2</sub>/V<sub>1</sub> - 1)D nR delta TShow answer & explanation →
Q61.
Entropy change when 0.5 kg of ice melts at 0 degrees C. Latent heat = 336 kJ/kg:
A 168 J/KB 336 J/KC 616 J/KD 168000 J/KShow answer & explanation →
Q64.
Mean free path of gas molecules increases when:
A Pressure increasesB Temperature decreasesC Both pressure and temperature decreaseD Pressure decreases or temperature increasesShow answer & explanation →
Q66.
Maxwell-Boltzmann distribution of molecular speeds: most probable speed v<sub>p</sub> compared to rms speed v<sub>rms</sub>:
A v<sub>p</sub> = v<sub>rms</sub>B v<sub>p</sub> < v<sub>rms</sub>C v<sub>p</sub> > v<sub>rms</sub>D v<sub>p</sub> = 0Show answer & explanation →
Q67.
In an Otto cycle, heat is added at:
A Constant pressureB Constant volumeC Constant temperatureD AdiabaticallyShow answer & explanation →
Q68.
For Van der Waals gas (a, b are constants): (P + an<sup>2</sup>/V<sup>2</sup>)(V - nb) = nRT. At high pressure compared to ideal gas, the gas:
A Is less compressible (harder to compress)B Is more compressible than an ideal gas at the same pressureC Behaves identically to an ideal gas under any pressureD Becomes more or less compressible only depending on temperature, not pressureShow answer & explanation →
Q69.
Triple point of water is at:
A 0 degrees C and 1 atmB 273.16 K and 611.7 PaC 100 degrees C and 0 PaD 25 degrees C and 1 atmShow answer & explanation →
Q70.
Joule-Thomson effect: when a real gas expands through a porous plug at constant enthalpy, temperature:
A Usually increases regardless of the gas's initial temperatureB Usually decreases regardless of the gas's initial temperatureC Can increase or decrease depending on inversion temperatureD Stays exactly constant throughout the entire expansion processShow answer & explanation →
Q72.
Entropy can be expressed as S = k ln(omega) where omega is:
A TemperatureB Number of microstatesC Pressure x VolumeD EnthalpyShow answer & explanation →
Q73.
A gas expands adiabatically from (P<sub>1</sub>, V<sub>1</sub>) to (P<sub>2</sub>, V<sub>2</sub>). Work done by gas:
A P<sub>1</sub>V<sub>1</sub> - P<sub>2</sub>V<sub>2</sub>B (P<sub>1</sub>V<sub>1</sub> - P<sub>2</sub>V<sub>2</sub>)/(gamma-1)C nCv(T<sub>1</sub>-T<sub>2</sub>)D Both B and CShow answer & explanation →
Q74.
If a system undergoes a cyclic process, net change in internal energy is:
A MaximumB PositiveC NegativeD ZeroShow answer & explanation →
Q75.
Clausius inequality states: for any process, cyclic integral of dQ/T:
A Is usually positiveB Is usually negativeC Is >= 0 for reversible, < 0 for irreversibleD Is <= 0Show answer & explanation →
Q77.
One mole of an ideal gas (γ = 1.4) is adiabatically compressed to half its volume. The ratio of final to initial temperature is approximately:
Show answer & explanation →
Q78.
One mole of an ideal gas expands isothermally from V to 2V at 300 K (R = 8.31 J/mol·K). The work done by the gas is about:
A 0.69 kJB 1.73 kJC 3.46 kJD 8.31 kJShow answer & explanation →
Q79.
A gas absorbs 200 J of heat and does 150 J of work on its surroundings. The change in its internal energy is:
A 50 JB 350 JC −50 JD 200 JShow answer & explanation →
Q80.
In a complete cyclic process a gas absorbs 100 J of heat. The net work done by the gas over the cycle is:
A 0 JB 50 JC 100 JD 200 JShow answer & explanation →
Q82.
An ideal gas undergoes free expansion into a vacuum inside an insulated container. Its temperature:
A increasesB decreasesC remains unchangedD becomes zeroShow answer & explanation →
Q83.
A refrigerator with coefficient of performance 4 extracts 400 J of heat from the cold reservoir per cycle. The work input required is:
A 40 JB 100 JC 400 JD 1600 JShow answer & explanation →