🧪 Chemistry · Class 11 · NEET & JEE
Equilibrium - Practice Questions with Answers 75 free MCQs on Equilibrium, each with its own worked answer and explanation. When forward and reverse reaction rates are equal, equilibrium is reached. Learn about Kc, Kp, Le Chatelier's principle, and acid-base equilibria, including pH, buffer solutions, and solubility product.
Take the timed Equilibrium chapterwise test → 75 practice questions on Equilibrium , sorted Easy → Hard. Try each one first, then open its answer page for the worked explanation. Want the full theory first? Read the Equilibrium notes .
Concentration Time Reactants Products equilibrium reached As the reaction proceeds, reactant concentration falls and product concentration rises until both level off at equilibrium.
Easy - 25 questions Q1.
The conjugate acid of ammonia (NH<sub>3</sub>) is:
A NH<sub>2</sub><sup>−</sup>B N<sub>2</sub>H<sub>4</sub>C NH<sub>4</sub><sup>+</sup>D OH<sup>−</sup>Show answer & explanation →
Q3.
According to Lewis, an acid is a species that:
A Accepts an electron pairB Donates an electron pairC Donates a proton onlyD Accepts a proton onlyShow answer & explanation →
Q4.
Chemical equilibrium is described as dynamic because:
A Both reactions have completely stoppedB Only the forward reaction keeps occurringC The measured concentrations keep changingD Opposing reactions continue at equal ratesShow answer & explanation →
Q5.
The equilibrium constant K<sub>c</sub> is dimensionless (has no units) when:
A Δn for the reaction is zeroB Δn is positiveC Δn is negativeD For all gaseous reactionsShow answer & explanation →
Q6.
Le Chatelier's principle states that when a stress is applied to a system at equilibrium, it will:
A Maintain the stressB Increase the stressC Oppose the changeD Stop the reactionShow answer & explanation →
Q7.
The equilibrium constant Kc is expressed in terms of:
A Moles under most conditions encounteredB Pressure as frequently observed in practiceC Molar concentrationD Temperature in many documented casesShow answer & explanation →
Q8.
At chemical equilibrium, the rate of forward reaction is:
A Greater than reverseB Less than reverseC Equal to reverseD ZeroShow answer & explanation →
Q9.
A very large value of Kc indicates that the reaction:
A Barely proceeds according to conventional understandingB Goes almost to completionC Is at equilibrium in routine practiceD Is endothermic overallShow answer & explanation →
Q10.
For N₂ + 3H₂ ⇌ 2NH₃, increasing pressure will:
A Shift equilibrium leftB Shift equilibrium rightC Have no effectD Stop the reactionShow answer & explanation →
Q11.
At equilibrium, which statement is correct?
A Concentrations of reactants equal productsB All reactions stopC Concentrations remain constantD Temperature changesShow answer & explanation →
Q15.
Adding a catalyst to a system at equilibrium:
A Shifts equilibrium toward the exothermic directionB Shifts equilibrium toward the endothermic directionC Increases the value of the equilibrium constant KcD Does not change the position of equilibriumShow answer & explanation →
Q16.
A reversible reaction reaches equilibrium when the forward and backward reaction rates become:
A greater than each otherB equalC very smallD zeroShow answer & explanation →
Q17.
At equilibrium, the measurable concentrations of reactants and products:
A become equalB remain constantC fall to zeroD keep increasingShow answer & explanation →
Q19.
For aA + bB ⇌ cC + dD, the expression Kc = [C]ᶜ[D]ᵈ divided by:
A [A][B]B [A]ᵃ[B]ᵇC [A]ᵃ + [B]ᵇD [C]ᶜ[D]ᵈShow answer & explanation →
Q20.
A catalyst added to a system at equilibrium:
A drives it fully forwardB drives it fully backwardC does not shift its positionD makes the reaction stopShow answer & explanation →
Q25.
Le Chatelier’s principle predicts how an equilibrium responds to a change in concentration, pressure or:
A solution colourB the catalystC temperatureD container sizeShow answer & explanation →
Medium - 25 questions Q26.
For A ⇄ B, K<sub>c</sub> = 4. Starting from 1 M A and no B, the equilibrium concentration of B is:
A 0.2 MB 0.5 MC 0.8 MD 1.0 MShow answer & explanation →
Q27.
For 2SO<sub>3</sub>(g) ⇌ 2SO<sub>2</sub>(g) + O<sub>2</sub>(g), the relation between K<sub>p</sub> and K<sub>c</sub> (Δn = +1) is:
A K<sub>p</sub> = K<sub>c</sub>B K<sub>p</sub> = K<sub>c</sub>/(RT)C K<sub>p</sub> = K<sub>c</sub>(RT)<sup>2</sup>D K<sub>p</sub> = K<sub>c</sub>(RT)Show answer & explanation →
Q28.
One mole each of H<sub>2</sub> and I<sub>2</sub> are placed in a 1 L flask; at equilibrium 0.8 mol of each has reacted. K<sub>c</sub> for H<sub>2</sub> + I<sub>2</sub> ⇌ 2HI is:
Show answer & explanation →
Q30.
A buffer contains 0.2 M CH<sub>3</sub>COOH and 0.2 M CH<sub>3</sub>COONa (pK<sub>a</sub> = 4.74). Its pH is:
Show answer & explanation →
Q31.
For PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), increasing pressure will:
A Favour PCl₅ formationB Favour PCl₃ and Cl₂C Have no effectD Increase KcShow answer & explanation →
Q32.
For N₂ + 3H₂ ⇌ 2NH₃, the relationship between Kp and Kc is:
A Kp = Kc(RT)²B Kp = Kc(RT)⁻²C Kp = Kc(RT)³D Kp = KcShow answer & explanation →
Q34.
The Henderson-Hasselbalch equation (pH = pKa + log[A⁻]/[HA]) is used to calculate:
A Kc of a reactionB pH of a buffer solutionC Enthalpy of neutralisationD EMF of a cellShow answer & explanation →
Q35.
The common ion effect causes solubility of a sparingly soluble salt to:
A IncreaseB DecreaseC Stay the sameD DoubleShow answer & explanation →
Q36.
For AgCl with Ksp = 1.8 × 10⁻¹⁰, its molar solubility is:
A 1.34 × 10⁻⁵ MB 1.8 × 10⁻¹⁰ MC 3.6 × 10⁻¹⁰ MD 1.8 × 10⁻⁵ MShow answer & explanation →
Q37.
For an exothermic reaction, increasing temperature will:
A Increase KB Decrease KC Not change KD First increase then decrease KShow answer & explanation →
Q38.
Which of the following increases Kc for an endothermic reaction?
A Decreasing temperatureB Increasing temperatureC Increasing pressureD Adding catalystShow answer & explanation →
Q39.
For the reaction 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) <=> 2SO<sub>3</sub>(g), how does adding an inert gas at constant volume affect the equilibrium?
A It increases the value of Kc for the reactionB It shifts the equilibrium towards SO<sub>2</sub> and O<sub>2</sub>C It shifts the equilibrium towards SO<sub>3</sub> formationD There is no effect on the equilibrium positionShow answer & explanation →
Q40.
A buffer solution is prepared by mixing a weak acid with its conjugate base. Why does this mixture resist large changes in pH when a small amount of acid or base is added?
A The conjugate base converts mainly into a strong base the moment any acid is added to it in the majority of documented casesB The mixture has a pH that stays fixed no matter how much acid or base is added to it as widely reported in standard reference materialC The weak acid neutralises added base while the conjugate base neutralises added acid, keeping their ratio steadyD The weak acid and conjugate base mostly evaporate before reacting with anything that is added later under most conditions studiedShow answer & explanation →
Q42.
Increasing the total pressure on the equilibrium N₂ + 3H₂ ⇌ 2NH₃ shifts it:
A backwardB forwardC not at allD to a stopShow answer & explanation →
Q43.
For a gaseous reaction in which Δn = 0, the value of Kp is:
A greater than KcB less than KcC equal to KcD equal to zeroShow answer & explanation →
Q44.
When the reaction quotient Q is smaller than the equilibrium constant K, the reaction proceeds:
A backwardB forwardC it is at equilibriumD it haltsShow answer & explanation →
Q45.
Adding a common ion to a solution of a weak acid decreases its:
A the resulting pH valueB degree of dissociationC the average molar massD the total solution volumeShow answer & explanation →
Q48.
According to the Brønsted–Lowry theory, a base is a species that:
A donates a protonB accepts a protonC releases OH⁻ ionsD gains electronsShow answer & explanation →
Q49.
For the exothermic equilibrium 2SO₂ + O₂ ⇌ 2SO₃, raising the temperature shifts it:
A forwardB backwardC not at allD only doubles KcShow answer & explanation →
Hard - 25 questions Q51.
A weak acid is 1% dissociated (alpha = 0.01) in a 0.1 M solution. Its dissociation constant K<sub>a</sub> is about:
A 1 x 10<sup>-3</sup>B 1 x 10<sup>-5</sup>C 1 x 10<sup>-7</sup>D 1 x 10<sup>-2</sup>Show answer & explanation →
Q52.
A buffer is made from 0.1 mol CH<sub>3</sub>COOH and 0.05 mol CH<sub>3</sub>COO<sup>−</sup> (pK<sub>a</sub> = 4.74). Its pH is about:
Show answer & explanation →
Q53.
If K<sub>c</sub> for N<sub>2</sub> + 3H<sub>2</sub> ⇌ 2NH<sub>3</sub> equals K, then K<sub>c</sub> for NH<sub>3</sub> ⇌ ½N<sub>2</sub> + 3/2 H<sub>2</sub> is:
A K<sup>2</sup>B 1/KC K<sup>−1/2</sup>D K<sup>1/2</sup>Show answer & explanation →
Q54.
Equal volumes of 2 × 10<sup>−3</sup> M BaCl<sub>2</sub> and 2 × 10<sup>−3</sup> M Na<sub>2</sub>SO<sub>4</sub> are mixed. Given K<sub>sp</sub>(BaSO<sub>4</sub>) = 1 × 10<sup>−10</sup>, will BaSO<sub>4</sub> precipitate?
A No, because Q < K<sub>sp</sub>B No, Q equals K<sub>sp</sub> exactlyC Yes, because Q > K<sub>sp</sub>D It cannot be predictedShow answer & explanation →
Q55.
Assertion (A): For an endothermic reaction, K<sub>c</sub> increases as temperature rises. Reason (R): Raising the temperature favours the forward (heat-absorbing) direction.
A Both A and R true; R correctly explains AB A is true but R is falseC A is false but R is trueD Both A and R true; R does not explain AShow answer & explanation →
Q56.
For H₂ + I₂ ⇌ 2HI, Kc = 45.9 at 490°C. If [H₂] = [I₂] = 0.1 M at equilibrium, [HI] is:
A 0.677 MB 0.215 MC 0.459 MD 0.046 MShow answer & explanation →
Q59.
Ksp of Ag₂CrO₄ = 1.12 × 10⁻¹². Its molar solubility is:
A 6.54 × 10⁻⁵ MB 1.06 × 10⁻⁶ MC 3.34 × 10⁻⁵ MD 1.12 × 10⁻⁴ MShow answer & explanation →
Q61.
The ionic product of water Kw increases with temperature because:
A Water ionisation is exothermicB Water ionisation is endothermicC Kw is independent of temperatureD Temperature reduces ion mobilityShow answer & explanation →
Q62.
AgCl (Ksp = 10⁻¹⁰) and AgBr (Ksp = 10⁻¹³) are both dissolved. When Ag⁺ is slowly added, which precipitates first?
A Cl⁻ precipitates firstB Br⁻ precipitates firstC Both precipitate togetherD Neither precipitatesShow answer & explanation →
Q63.
For an exothermic reaction with Kc = 0.04 at 1000 K, as temperature increases Kc will:
A IncreaseB DecreaseC Stay the sameD First increase then decreaseShow answer & explanation →
Q64.
A 0.1 M solution of a weak base BOH has a degree of dissociation of 0.02. What is the value of Kb for this base?
A 4 x 10<sup>-5</sup>B 4 x 10<sup>-3</sup>C 2 x 10<sup>-5</sup>D 2 x 10<sup>-3</sup>Show answer & explanation →
Q65.
For the equilibrium N<sub>2</sub>O<sub>4</sub>(g) <=> 2NO<sub>2</sub>(g), the total pressure at equilibrium is P and the degree of dissociation of N<sub>2</sub>O<sub>4</sub> is alpha. Which expression correctly gives Kp in terms of alpha and P?
A Kp = 4 alpha<sup>2</sup> P / (1 - alpha<sup>2</sup>)B Kp = 2 alpha P / (1 - alpha<sup>2</sup>)C Kp = alpha<sup>2</sup> P / (1 - alpha)D Kp = 4 alpha P<sup>2</sup> / (1 + alpha)Show answer & explanation →
Q66.
For a sparingly soluble salt AB with molar solubility S, its solubility product is:
A Ksp = SB Ksp = S²C Ksp = 2SD Ksp = S³Show answer & explanation →
Q67.
By Ostwald’s dilution law for a weak acid, Ka in terms of concentration C and degree of dissociation α is:
A α² C on its ownB α² C/(1 − α)C α times C squaredD C divided by αShow answer & explanation →
Q68.
In the Henderson–Hasselbalch equation, the pH of an acidic buffer is pH = pKa +:
A log([acid]/[salt])B log([salt]/[acid])C the ratio [salt]/[acid]D the value of pKaShow answer & explanation →
Q69.
The degree of hydrolysis of the salt of a weak acid and a strong base increases on:
A reducing the dilutionB increasing the dilutionC adding a common ionD cooling the solutionShow answer & explanation →
Q71.
A large equilibrium constant (K ≫ 1) indicates that at equilibrium:
A reactants are favouredB products are favouredC amounts are equalD no reaction occursShow answer & explanation →
Q73.
Adding an inert gas to a gaseous equilibrium at constant volume:
A shifts it strongly forwardB shifts it strongly backwardC leaves the position unchangedD doubles the value of KShow answer & explanation →
Q74.
Given ΔG° = −2.303 RT log K, a positive value of ΔG° means the equilibrium constant K is:
A greater than 1B less than 1C equal to 1D infiniteShow answer & explanation →
Q75.
A salt formed from a strong acid and a weak base, when dissolved in water, gives a solution that is:
A acidicB basicC neutralD amphotericShow answer & explanation →