83 practice questions on Gravitation , sorted Easy → Hard. Try each one first, then open its answer page for the worked explanation. Want the full theory first? Read the Gravitation notes .
Variation of g with Height and Depth g g_surface Above surface: g ∝ 1/r² (falls off curving down) Below surface: g ∝ r (falls off LINEARLY) Earth's surface (r = R) centre (r=0): g=0 g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.
Easy - 24 questions Q1.
The acceleration due to gravity of a freely falling body does NOT depend on:
A the mass of the bodyB the radius of the planetC the mass of the planetD the height above the surfaceShow answer & explanation →
Q2.
Taking the reference at infinity, the gravitational potential energy of a two-body system is:
A always positiveB always negativeC always zeroD positive at infinityShow answer & explanation →
Q3.
The value of g on the Earth is greatest:
A at the equatorB on a mountain topC at the polesD at sea level near the equatorShow answer & explanation →
Q4.
The escape velocity from a planet depends on:
A the mass of the projectileB the launch directionC the projectile shapeD the planet mass and radiusShow answer & explanation →
Q5.
Value of gravitational acceleration g at Earth's surface is approximately:
A 9.8 m/s<sup>2</sup>B 8.9 m/s<sup>2</sup>C 10.8 m/s<sup>2</sup>D 6.7 m/s<sup>2</sup>Show answer & explanation →
Q6.
As we go higher from Earth's surface, the value of g:
A IncreasesB DecreasesC Stays constantD Becomes zero at 1 kmShow answer & explanation →
Q7.
Universal gravitational constant G has the value:
A 6.67 x 10<sup>-11</sup> N m<sup>2</sup>/kg<sup>2</sup>B 9.8 m/s<sup>2</sup>C 6.67 x 10<sup>-11</sup> N/m<sup>2</sup>D 9.8 N/kg<sup>2</sup>Show answer & explanation →
Q8.
Kepler's second law (equal areas in equal time) is a consequence of:
A Conservation of energyB Conservation of angular momentumC Conservation of linear momentumD Newton's third lawShow answer & explanation →
Q10.
The gravitational force between two masses is proportional to:
A Sum of massesB Product of massesC Difference of massesD Square root of massesShow answer & explanation →
Q11.
Orbital velocity of a satellite near Earth's surface is approximately:
A 3 km/sB 7.9 km/sC 11.2 km/sD 28 km/sShow answer & explanation →
Q13.
An astronaut in an orbiting satellite experiences weightlessness because:
A No gravity in space in most cases under typical conditionsB Gravity is zero at that height according to standard textbooksC Both satellite and astronaut are in free fallD The satellite is too far from Earth in general practiceShow answer & explanation →
Q14.
Gravitational force is a _____ force:
A Contact forceB Short-range forceC Long-range, always attractiveD Long-range, attractive or repulsiveShow answer & explanation →
Q15.
If distance between two masses doubles, gravitational force becomes:
A DoubleB HalfC One-fourthD Four timesShow answer & explanation →
Q16.
Kepler's third law states that T<sup>2</sup> is proportional to:
A rB r<sup>2</sup>C r<sup>3</sup>D r<sup>4</sup>Show answer & explanation →
Q21.
A planet closer to the Sun moves _____ compared to a distant planet:
A SlowerB FasterC Same speedD Speed depends on massShow answer & explanation →
Q22.
Which force keeps the Moon in orbit around Earth?
A Centrifugal forceB Normal forceC Gravitational forceD Magnetic forceShow answer & explanation →
Q23.
Relation between escape velocity (ve) and orbital velocity (vo) at Earth's surface:
A ve = voB ve = 2voC ve = sqrt(2) x voD vo = sqrt(2) x veShow answer & explanation →
Medium - 24 questions Q25.
The escape velocity from Earth is 11.2 km/s. If a body is projected at 22.4 km/s, its speed far away from Earth (ignoring other bodies) is about:
A 22.4 km/sB 11.2 km/sC 19.4 km/sD 33.6 km/sShow answer & explanation →
Q26.
A planet orbits the Sun at four times the Earth-Sun distance. Its orbital period (year) is about:
A 64 yearsB 16 yearsC 4 yearsD 8 yearsShow answer & explanation →
Q27.
A body weighs 100 N at the Earth surface. At a depth equal to one-fourth of the Earth radius, its weight is:
Show answer & explanation →
Q28.
The orbital period of a satellite skimming very close to a planet's surface depends only on the planet's:
A massB densityC radiusD temperatureShow answer & explanation →
Q29.
A satellite orbits at height equal to Earth's radius R (i.e., at distance 2R from center). Orbital velocity compared to surface orbital velocity:
A SameB 1/sqrt(2) timesC 1/2 timesD sqrt(2) timesShow answer & explanation →
Q31.
Time period of satellite at height h from Earth's surface:
A 2*pi*sqrt(R/g)B 2*pi*sqrt((R+h)<sup>3</sup>/(GM))C 2*pi*sqrt((R+h)/g)D 2*pi*sqrt(GM/R)Show answer & explanation →
Q32.
Two bodies of mass M and m are at distance r. At what distance from M is the gravitational field zero?
A r*sqrt(M)/(sqrt(M)+sqrt(m))B r*M/(M+m)C r*sqrt(m)/(sqrt(M)+sqrt(m))D r/2Show answer & explanation →
Q33.
If Earth suddenly stopped rotating, weight of a person at equator would:
A IncreaseB DecreaseC Stay sameD Become zeroShow answer & explanation →
Q34.
Orbital velocity of satellite at height h from Earth (radius R, mass M):
A sqrt(GM/R)B sqrt(GM/(R+h))C sqrt(2GM/(R+h))D sqrt(gR<sup>2</sup>/(R+h))Show answer & explanation →
Q36.
Total mechanical energy of a satellite in circular orbit of radius r (mass m, Earth mass M):
A -GMm/rB -GMm/(2r)C GMm/(2r)D GMm/rShow answer & explanation →
Q37.
Gravitational potential V at distance r from mass M is:
A GMm/rB -GM/rC GM/r<sup>2</sup>D -GMm/r<sup>2</sup>Show answer & explanation →
Q38.
Energy required to send satellite from surface to orbit at radius r=2R (R=Earth's radius, M=Earth's mass):
A GMm/(4R)B GMm/(2R)C 3GMm/(4R)D GMm/RShow answer & explanation →
Q39.
At poles, g is slightly greater than at equator because:
A The polar radius of Earth is larger than the equatorial radiusB Earth's rotation alone increases g everywhere uniformlyC Polar radius is smaller so closer to centerD Earth's mass distribution is concentrated more heavily near the polesShow answer & explanation →
Q40.
Gravitational field intensity at surface of Earth (radius R, mass M) is:
A G/R<sup>2</sup>B GM/R<sup>2</sup>C GMm/R<sup>2</sup>D 2GM/R<sup>2</sup>Show answer & explanation →
Q42.
If mass of Earth doubled but radius stayed same, escape velocity would:
A Halve under typical conditionsB Stay same according to standard textbooksC Increase by sqrt(2)D Double in general practiceShow answer & explanation →
Q44.
Black holes have escape velocity equal to or greater than:
A Orbital velocityB Speed of lightC Speed of soundD Speed of EarthShow answer & explanation →
Q46.
For an orbit to be geosynchronous, it must be over:
A North PoleB EquatorC Tropic of CancerD Any latitudeShow answer & explanation →
Q47.
Value of g at depth d below Earth's surface:
A g(1-d/R)B g(1-2d/R)C g(1-d<sup>2</sup>/R<sup>2</sup>)D g*d/RShow answer & explanation →
Q48.
The gravitational PE of a body of mass m at distance r from Earth's center (M = Earth mass) is:
A -GMm/rB GMm/rC -GMm/r<sup>2</sup>D mghShow answer & explanation →
Hard - 35 questions Q49.
The escape velocity from a planet is 11.2 km/s. If its radius is doubled while its mean density stays the same, the new escape velocity is:
A 22.4 km/sB 11.2 km/sC 5.6 km/sD 44.8 km/sShow answer & explanation →
Q50.
The gravitational potential energy of a 2 kg mass resting on a planet surface is −8 × 10<sup>7</sup> J. The escape speed from that surface is about:
A 4.5 km/sB 6.3 km/sC 12.6 km/sD 8.9 km/sShow answer & explanation →
Q51.
Two equal point masses M are separated by a distance 2a. The gravitational potential at the midpoint between them is:
A -GM/2aB -GM/aC -2GM/aD -4GM/aShow answer & explanation →
Q52.
A planet has the same mean density as another but twice its radius. Its escape velocity, compared with the smaller planet, is:
A it halvesB it stays the sameC it quadruplesD it doublesShow answer & explanation →
Q53.
A body is dropped from rest at a height equal to the Earth radius R above the surface. Its speed on reaching the surface is about (g = 10 m/s<sup>2</sup>, R = 6.4×10<sup>6</sup> m):
A 8 km/sB 2 km/sC 4 km/sD 11 km/sShow answer & explanation →
Q54.
A geostationary satellite orbits at approximately what height above the Earth surface?
A 3,600 kmB 36,000 kmC 3,60,000 kmD 360 kmShow answer & explanation →
Q55.
At a distance r from the centre inside a uniform solid sphere of radius R (r < R), the gravitational field is proportional to:
A 1/r<sup>2</sup>B 1/rC rD r<sup>2</sup>Show answer & explanation →
Q56.
Planet A has twice the mass and four times the radius of planet B. Ratio of g<sub>A</sub> to g<sub>B</sub>:
Show answer & explanation →
Q58.
A satellite changes orbit from r<sub>1</sub> to r<sub>2</sub> (r<sub>2</sub> > r<sub>1</sub>). Change in KE is:
A Positive (increases)B Negative (decreases)C ZeroD Depends on massShow answer & explanation →
Q59.
Angular velocity of Moon around Earth: T = 27 days. Angular velocity in rad/s:
A 2.7 x 10<sup>-6</sup> rad/sB 2.5 x 10<sup>-6</sup> rad/sC 7.3 x 10<sup>-5</sup> rad/sD 1.2 x 10<sup>-5</sup> rad/sShow answer & explanation →
Q60.
A body is projected vertically upward from Earth's surface with speed ve/2 (ve = escape speed). Max height reached:
Show answer & explanation →
Q61.
Escape velocity on the Moon (g<sub>moon</sub> = g/6, R<sub>moon</sub> = R/4):
A ve/sqrt(24)B ve*sqrt(6)/4C ve/sqrt(6)D ve/4Show answer & explanation →
Q62.
A satellite is in circular orbit. When it loses energy due to air resistance, its orbital speed:
A DecreasesB IncreasesC Stays sameD OscillatesShow answer & explanation →
Q63.
A satellite at radius r from Earth center has angular momentum L. If radius decreases to r/4 (no external torque), new angular momentum is:
Show answer & explanation →
Q64.
A planet is at perihelion (closest) and aphelion (farthest). Speed ratio v<sub>perihelion</sub> : v<sub>aphelion</sub> equals:
A r<sub>aph</sub> : r<sub>per</sub>B r<sub>per</sub> : r<sub>aph</sub>C r<sub>aph</sub><sup>2</sup> : r<sub>per</sub><sup>2</sup>D r<sub>per</sub><sup>2</sup> : r<sub>aph</sub><sup>2</sup>Show answer & explanation →
Q65.
Gravitational potential at a point is -5 x 10<sup>7</sup> J/kg. Work done to bring 1 kg mass from infinity to this point is:
A 5 x 10<sup>7</sup> JB -5 x 10<sup>7</sup> JC ZeroD InfinityShow answer & explanation →
Q66.
Tidal forces on Earth due to Moon cause:
A Ocean tides mainly on the side facing Moon under typical conditionsB Ocean bulges on both sides facing and opposite MoonC No effect on Earth according to standard textbooksD Mainly earthquakes in general practice as frequently describedShow answer & explanation →
Q67.
If Earth's mass is M, radius R, orbital velocity at height h = R (i.e., r = 2R) in terms of g and R:
A sqrt(gR/2)B sqrt(gR)C sqrt(2gR)D sqrt(gR/4)Show answer & explanation →
Q68.
Minimum energy needed to launch a satellite from Earth's surface to circular orbit at radius 2R:
A GMm/(2R)B 3GMm/(4R)C 5GMm/(4R)D GMm/RShow answer & explanation →
Q69.
Gravitational field is zero at all interior points of a uniform hollow spherical shell. This is because:
A The total mass of the shell is negligible compared to the test pointB Forces from all shell mass cancel inside due to symmetryC Gravity acts as a repulsive force for any point inside the shellD The mass density at every interior point of the shell is zeroShow answer & explanation →
Q70.
Two satellites orbit at 2R and 3R from Earth center. Period ratio T<sub>1</sub>:T<sub>2</sub>:
A 2:3, treating the period as directly proportional to radiusB 4:9, treating the period as proportional to the square of radiusC 2*sqrt(2):3*sqrt(3)D 8:27, treating the period as proportional to the cube of radiusShow answer & explanation →
Q72.
Gravitational force between two 1 kg masses 1 m apart is:
A 6.67 x 10<sup>-11</sup> NB 9.8 NC 1 ND 6.67 x 10<sup>-8</sup> NShow answer & explanation →
Q73.
A tunnel is drilled through Earth's center. A ball dropped into it undergoes:
A Uniform accelerationB Free fall at g throughoutC Simple harmonic motionD Uniform velocityShow answer & explanation →
Q74.
Binary stars of mass M each orbit their center of mass at distance d apart. Orbital period T in terms of G, M, d:
A 2*pi*sqrt(d<sup>3</sup>/(2GM))B 2*pi*sqrt(d<sup>3</sup>/(GM))C pi*sqrt(d<sup>3</sup>/(2GM))D 2*pi*sqrt(d<sup>3</sup>/(4GM))Show answer & explanation →
Q75.
Chandrasekhar limit refers to the maximum mass of:
A A planetB A black holeC A white dwarf starD A neutron starShow answer & explanation →
Q76.
A planet has the same radius as Earth but twice its mass. If Earth escape velocity is 11.2 km/s, the escape velocity from this planet is:
A 11.2 km/sB 15.8 km/sC 22.4 km/sD 5.6 km/sShow answer & explanation →
Q77.
A satellite orbits at radius r with period T. If the orbital radius is increased to 4r, the new period is:
Show answer & explanation →
Q78.
The acceleration due to gravity at a depth equal to half the Earth radius (compared with the surface value g) is:
Show answer & explanation →
Q80.
The total mechanical energy of a satellite of mass m in a circular orbit of radius r around a planet of mass M is:
A −GMm/rB −GMm/2rC +GMm/2rD −GMm/4rShow answer & explanation →
Q81.
A planet moves in an elliptical orbit. If its aphelion distance is 4 times its perihelion distance, the ratio of its perihelion speed to aphelion speed is:
Show answer & explanation →
Q82.
A planet has twice the radius of Earth but the same mean density. The surface gravity on the planet, compared with Earth g, is:
Show answer & explanation →
Q83.
Two satellites move in the same circular orbit around Earth, one having twice the mass of the other. Their orbital speeds are:
A equalB the heavier one is fasterC the lighter one is fasterD the heavier one is slowerShow answer & explanation →