68 practice questions on Sequences and Series , sorted Easy → Hard. Try each one first, then open its answer page for the worked explanation. Want the full theory first? Read the Sequences and Series notes .
Each bar grows by the common difference d=3 a1=2 a2=5 a3=8 a4=11 d=3 Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.
Easy - 20 questions Q10.
The sequence 1, 4, 9, 16,... is:
A An AP with common difference 3B A GP with common ratio 2C Squares of natural numbersD An HP with reciprocals in APShow answer & explanation →
Medium - 20 questions Q34.
If the sum of an infinite GP is 3 and sum of squares of its terms is 9/5, find the series.
A 1, 2/3, 4/9,...B 2, 4/3, 8/9,...C 3/2, 1, 2/3,...D 1, 1, 1,...Show answer & explanation →
Hard - 28 questions Q44.
In a GP, if a₁ + a₂ + a₃ = 13 and a₁a₂a₃ = 27, find the common ratio.
A 1/3 or 3B 2 or 1/2C 1 or 1D 3 or -3Show answer & explanation →
Q46.
The sum of an arithmetic-geometric series a + (a+d)r + (a+2d)r² + ... to infinity (|r|<1) is:
A a/(1-r) + dr/(1-r)²B a/(1-r)C dr/(1-r)D a + dr/(1-r)²Show answer & explanation →
Q48.
If x, y, z are in GP and a<sup>x</sup> = b<sup>y</sup> = c<sup>z</sup>, then a, b, c are in:
A APB GPC HPD No relationShow answer & explanation →
Q51.
Between two numbers a and b, n geometric means are inserted. The product of all n means equals:
A (ab)<sup>n/2</sup>B (ab)<sup>n</sup>C ab × nD n√(ab)Show answer & explanation →
Q52.
If the sum of first n terms is 3n² + 5n, is it AP? Find the common difference.
A Yes, d = 6B No, it is not APC Yes, d = 3D Yes, d = 5Show answer & explanation →
Q53.
Sum: 1/(1×2×3) + 1/(2×3×4) + ... to n terms =
A 1/4 - 1/(2(n+1)(n+2))B 1/4, without the correction term for finite nC 1/2(n+1), a partial telescoping resultD n/(n+1)(n+2), a related but different ratioShow answer & explanation →
Q54.
The sum 2 + 2² + 2³ + ... + 2<sup>n</sup> =
A 2<sup>n+1</sup> - 2B 2<sup>n</sup> - 1C 2<sup>n+1</sup>D 2(2<sup>n</sup> - 1)Show answer & explanation →
Q55.
If three numbers are in HP, their reciprocals are in AP. If HP is 1/2, 1/3, 1/4, the AP is:
A 2, 3, 4B 4, 3, 2C 1/4, 1/3, 1/2D 2, 4, 6Show answer & explanation →
Q57.
Sum of the series: 1 + 2x + 3x² + 4x³ + ... to infinity (|x| < 1) =
A 1/(1-x)²B 1/(1-x)C x/(1-x)²D 1/(1-x) + 1Show answer & explanation →
Q58.
If a, b, c are in GP and p, q, r are in AP, then a<sup>p</sup> × b<sup>q</sup> × c<sup>r</sup> =
A b<sup>p+q+r</sup>B abcC b<sup>p+r</sup> × b<sup>q</sup>D abc = b<sup>p+q+r</sup>Show answer & explanation →
Q68.
The sum of the first n terms of the series 9 + 99 + 999 + ... is:
A (10<sup>n+1</sup> − 9n − 10)/9B (10<sup>n+1</sup> − 10)/9 + nC (10<sup>n+1</sup> − 9n − 10)/81D 10<sup>n+1</sup>/9 − nShow answer & explanation →